The above example shows 11:22:33 is between 9AM and 5PM.
Thus, I divided number of seconds by 60 to get number of minutes. I assume only minute-level time is wanted. # Convert character to a "Period" class by lubridate, shows in form of H M SĪ little more about using them as numeric: If you want more, personally, I like lubridate package when dealing with time data, especially timestamps with dates although it's not the focus of this post at all. I just want to introduce lubridate a little bit since it's easier to use, and flexible with time format. Thanks for the feedback and sorry for the confusion I have edited it a bit to clarify.įirst, chron package and strptime with fixed format both work well as demonstrated in other answers. Graphics: tab SubstracTimes(TimeEnter, TimeExit) Table(hours(Enter)) # Counts of entries each hour Table(cut(hours(Enter), breaks = c(0, 10, 17, 24))) # Counts for indicated hours Mean(Exit > "17:00:00") # fraction exiting after 5pm Use the "times" class found in the chron package: library(chron)Įnter "17:00:00") # no exiting after 5pm
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